In many probability situations in which finite sample description spaces arise it may be assumed that all descriptions are equally likely; that is, all descriptions in \(S\) have equal probability of occurring. More precisely, we define the sample description space \(S=\left\{D_{1}, D_{2}, \ldots, D_{N}\right\}\) as having equally likely descriptions if all the single-member events on \(S\) have equal probabilities, so that
\[P\left[\left\{D_{1}\right\}\right]=P\left[\left\{D_{2}\right\}\right]=\cdots=P\left[\left\{D_{N}\right\}\right]=\frac{1}{N}. \tag{7.1}\]
It should be clear that each of the single-member events \(\left\{D_{i}\right\}\) has probability \((1 / N)\) , since there are \(N\) such events, each of which has equal probability, and the sum of their probabilities must equal 1, the probability of the certain event.
The computation of the probability of an event, defined on a sample description space with equally likely descriptions, can be reduced to the computation of the size of the event. By (6.1) , the probability of \(E\) is equal to \((1 / N)\) , multiplied by the number of descriptions in \(E\) . In other words, the probability of \(E\) is equal to the ratio of the size of \(E\) to the size of \(S\) . If, for a set \(E\) of finite size, we let \(N[E]\) denote the size of \(E\) (the number of members of \(E\) ), then the foregoing conclusions can be summed up in a basic formula:
Formula for Calculating the Probabilities of Events When the Sample Description Space \(S\) Is Finite and All Descriptions Are Equally Likely : For any event \(E\) on \(S\) \[P[E]=\frac{N[E]}{N[S]}=\frac{\text { size of } E}{\text { size of } S}. \tag{7.2}\]
This formula can be stated in words. If an event is defined as a subset of a finite sample description space, whose descriptions are all equally likely, then the probability of the event is the ratio of the number of descriptions belonging to it to the total number of descriptions. This statement may be regarded as a precise formulation of the classical “equal-likelihood” definition of the probability of an event, first explicitly formulated by Laplace in 1812.
The Laplacean “Equal-Likelihood” Definition of the Probability of a Random Event . The probability of a random event is the ratio of the number of cases favoring it to the number of all possible cases, when nothing leads us to believe that one of these cases ought to occur rather than the others. This renders them, for us, equally possible.
In view of (7.2), one sees that in adopting the axiomatic definition of probability given in section 5 one does not thereby reject the Laplacean definition of probability. Rather, the Laplacean definition is a special case of the axiomatic definition, corresponding to the case in which the sample description space is finite and the probability distribution on the sample description space is a uniform one. This is an alternate way of saying that all descriptions are equally likely.
We may now state a mathematical model for the experiment of drawing a ball from an urn containing six balls, numbered 1 to 6, of which balls one to four are colored white and the remaining two balls are nonwhite. For the sample description space \(S\) of the experiment we take \(S=\) \(\{1,2,3,4,5,6\}\) . The event \(A\) that the ball drawn is white is then given as a subset of \(S\) by \(A=\{1,2,3,4\}\) . To compute the probability of \(A\) , we must adopt a probability function \(P[\cdot]\) on \(S\) . If we assume that the descriptions in \(S\) are equally likely, then \(P[\cdot]\) is determined by (7.2), and \(P[A]=\frac{2}{3}\) . On the other hand, we may specify a different probability function \(P[\cdot]\) , specified on the single-member events of \(S\) :
\[P[\{1\}]=P[\{2\}]=P[\{3\}]=P[\{4\}]=\frac{1}{8}, \quad P[\{5\}]=P[\{6\}]=\frac{1}{4}.\]
Then the function \(P[\cdot]\) is determined by (6.1) , and \(P[A]=\frac{1}{2}\) .
We have thus stated two different mathematical models for the experiment of drawing a ball from an urn. Only the results of actual experiments can decide which of the two models is realistic. However, as we study the properties of various models in the course of this book, theoretical grounds will appear for preferring some kinds of models over others.
Example 7A . Find the probability that the thirteenth day of a randomly chosen month is a Friday.
Solution
The sample description space of the experiment of observing the day of the week upon which the thirteenth day of a randomly chosen month will fall is clearly \(S=\) {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday \(\}\) . We are seeking \(P[\{\) Friday \(\}]\) . If we assume equally likely descriptions, then \(P[\{\) Friday \(\}]=\frac{1}{7}\) . However, would one believe this conclusion in the face of the following alternative mathematical model? To define a probability function on \(S\) , note that our calendar has a period of 400 years, since every fourth year is a leap year, except for years such as 1700,1800, and 1900, at which a new century begins (or an old century ends) but which are not multiples of 400. In 400 years there are 97 leap years and exactly 20,871 weeks. For each of the 4800 dates between 1600 and 2000 that is the thirteenth day of some month one may determine the day of the week on which it falls. For any given day \(x\) of the week let us define \(P[\{x\}]\) as the relative frequency of occurrence of \(x\) in the list of 4800 days of the week which arise as the thirteenth day of some month. It may be shown by a direct but tedious enumeration [see American Mathematical Monthly , Vol. 40 (1933), p. 607] that
| \(x \quad\) | Sunday | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday |
|---|---|---|---|---|---|---|---|
| \(P[\{x\}]\) | \(\frac{687}{4800}\) | \(\frac{685}{4800}\) | \(\frac{685}{4800}\) | \(\frac{687}{4800}\) | \(\frac{684}{4800}\) | \(\frac{688}{4800}\) | \(\frac{684}{4800}\) |
Note that the probability model given by (7.3) leads to the conclusion that the thirteenth of the month is more likely to be a Friday than any other day of the week!
Example 7B . Consider a state (such as Illinois) in which the license plates of automobiles are numbered serially, beginning with 1. Assuming that there are 3,000,000 automobiles registered in the state, what is the probability that the first digit on the license plate of an automobile selected at random will be the digit 1?
Solution
As the first digit on the license of a car, one may observe any integer in the set \(\{1,2,3,4,5,6,7,8,9\}\) . Consequently, one may be tempted to adopt this set as the sample description space. If one assumes that all sample descriptions in this space are equally likely, then one would arrive at the conclusion that the probability is \(\frac{1}{9}\) that the digit \(I\) will be the first digit on the license plate of an automobile randomly selected from the automobiles registered in Illinois. However, would one believe this conclusion in the face of the following alternative model? As a result of observing the number on a license plate, one may observe any number in the set \(S\) consisting of all integers 1 to \(3,000,000\) . The event \(A\) that one observes a license plate whose first digit is 1 consists of the integers enumerated in Table 7A. The set \(A\) has size \(N[A]=1,111,111\) . If the set \(S\) is adopted as the sample description space and all descriptions in \(S\) are assumed to be equally likely, then
\[P[A]=\frac{N[A]}{N[S]}=\frac{1,111,111}{3,000,000}=0.37037.\]
| All License Plates in the Following Intervals Have First Digit \(1\) | Number of Integers In This Interval |
| 1 | 1 |
| \(10-19\) | 10 |
| \(100-199\) | 100 |
| \(1000-1999\) | 1000 |
| \(10,000-19,999\) | 10,000 |
| \(100,000-199,999\) | 100,000 |
| \(1,000,000-1,999,999\) | \(1,000,000\) |
Exercises
7.1 . Suppose that a die (with faces marked \(l\) to 6) is loaded in such a manner that, for \(k=1, \ldots, 6\) , the probability of the face marked \(k\) turning up when the die is tossed is proportional to \(k\) . Find the probability of the event that the outcome of a toss of the die will be an even number.
Answer
\(12 / 21\) .
7.2. What is the probability that the thirteenth of the month will be (i) a Friday or a Saturday, (ii) a Saturday, Sunday, or Monday?
7.3 . Let a number be chosen from the integers 1 to 100 in such a way that each of these numbers is equally likely to be chosen. What is the probability that the number chosen will be (i) a multiple of 7, (ii) a multiple of 14?
Answer
(i) 0.14, (ii) 0.07.
7.4 . Consider a state in which the license plates of automobiles are numbered serially, beginning with 1. What is the probability that the first digit on the license plate of an automobile selected at random will be the digit 1, assuming that the number of automobiles registered in the state is equal to (i) 999,999, (ii) \(1,000,000\) , (iii) \(1,500,000\) , (iv) \(2,000,000\) , (v) \(6,000,000\) ?
7.5 . What is the probability that a ball, drawn from an urn containing 3 red balls, 4 white balls, and 5 blue balls, will be white? State carefully any assumptions that you make.
Answer
\(\frac{1}{3}\) .
7.6 . A research problem . Using the same assumptions as those with which the table in (7.3) was derived, find the probability that Christmas (December 25) is a Monday. Indeed, show that the probability that Christmas will fall on a given day of the week is supplied by the following table:
| \(x\) | Sunday | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday |
|---|---|---|---|---|---|---|---|
| \(P[\{x\}]\) | \(\frac{58}{400}\) | \(\frac{56}{400}\) | \(\frac{58}{400}\) | \(\frac{57}{400}\) | \(\frac{57}{400}\) | \(\frac{58}{400}\) | \(\frac{56}{400}\) |