Transformations of rank one

We conclude our discussion of rank by a description of the matrices of linear transformations of rank 1 .

Theorem 1. If a linear transformation A on a finite-dimensional vector space 𝒱 is such that ρ ( A ) 1 (that is, ρ ( A ) = 0 or ρ ( A ) = 1 ), then the elements of the matrix [ A ] = ( α i j ) of A have the form α i j = β i γ j in every coordinate system; conversely if the matrix of A has this form in some one coordinate system, then ρ ( A ) 1 .

Proof. If ρ ( A ) = 0 , then A = 0 , and the statement is trivial. If ρ ( A ) = 1 , that is, ( A ) is one-dimensional, then there exists in ( A ) a non-zero vector x 0 (a basis in ( A ) ) such that every vector in ( A ) is a multiple of x 0 . Hence, for every x , A x = y 0 x 0 , where the scalar coefficient y 0 ( = y 0 ( x ) ) depends, of course, on x . The linearity of A implies that y 0 is a linear functional on 𝒱 . Let 𝒳 = { x 1 , , x n } be a basis in 𝒱 , and let ( α i j ) be the corresponding matrix of A , so that A x j = i α i j x i . If \mathcal{X}^{\prime}=\{y_{1}, \ldots, y_{n}\} is the dual basis in \mathcal{V}^{\prime} , then (cf. Section: Adjoints of projections , (2)) α i j = [ A x j , y i ] . In the present case α i j = [ y 0 ( x j ) x 0 , y i ] = y 0 ( x j ) [ x 0 , y i ] = [ x 0 , y i ] [ x j , y 0 ] ; in other words, we may take β i = [ x 0 , y i ] and γ j = [ x j , y 0 ] .

Conversely, suppose that in a fixed coordinate system 𝒳 = { x 1 , , x n } the matrix ( α i j ) of A is such that α i j = β i γ j . We may find a linear functional y 0 such that γ j = [ x j , y 0 ] , and we may define a vector x 0 by x 0 = k β k x k . The linear transformation A ~ defined by A ~ x = y 0 ( x ) x 0 is clearly of rank one (unless, of course, α i j = 0 for all i and j ), and its matrix ( α ~ i j ) in the coordinate system 𝒳 is given by α ~ i j = [ A ~ x j , y i ] (where \mathcal{X}^{\prime}=\{y_{1}, \ldots, y_{n}\} is the dual basis of 𝒳 ). Hence α ~ i j = [ y 0 ( x j ) x 0 , y i ] = [ x 0 , y i ] [ x j , y 0 ] = β i γ j , and, since A and A ~ have the same matrix in one coordinate system, it follows that A ~ = A . This concludes the proof of the theorem. ◻

The following theorem sometimes makes it possible to apply Theorem 1 to obtain results about an arbitrary linear transformation.

Theorem 2. If A is a linear transformation of rank ρ on a finite-dimensional vector space 𝒱 , then A may be written as the sum of ρ transformations of rank one.

Proof. Since A 𝒱 = ( A ) has dimension ρ , we may find ρ vectors x 1 , , x ρ that form a basis for ( A ) . It follows that, for every vector x in 𝒱 , we have A x = i = 1 ρ ξ i x i , where each ξ i depends, of course, on x ; we write ξ i = y i ( x ) . It is easy to see that y i is a linear functional. In terms of these y i we define, for each i = 1 , , ρ , a linear transformation A i by A i x = y i ( x ) x i . It follows that each A i has rank one and A = i = 1 ρ A i . (Compare this result with Section: Linear transformations , example (2).) ◻

A slight refinement of the proof just given yields the following result.

Theorem 3. Corresponding to any linear transformation A on a finitedimensional vector space 𝒱 there is an invertible linear transformation P for which P A is a projection.

Proof. Let and 𝒩 , respectively, be the range and the null-space of A , and let { x 1 , , x ρ } be a basis for . Let x ρ + 1 , , x n be vectors such that { x 1 , , x n } is a basis for 𝒱 . Since x i is in for i = 1 , , ρ , we may find vectors y i such that A y i = x i ; finally, we choose a basis for 𝒩 , which we may denoted by { y ρ + 1 , , y n } . We assert that { y 1 , , y n } is a basis for 𝒱 . We need, of course, to prove only that the y ’s are linearly independent. For this purpose we suppose that i = 1 n α i y i = 0 ; then we have (remembering that for i = ρ + 1 , , n the vector y i belongs to 𝒩 ) A ( i = 1 n α i y i ) = i = 1 ρ α i x i = 0 , whence α 1 = = α ρ = 0 . Consequently i = ρ + 1 n α i y i = 0 ; the linear independence of y ρ + 1 , , y n shows that the remaining α ’s must also vanish.

A linear transformation P , of the kind whose existence we asserted, is now determined by the conditions P x i = y i , i = 1 , , n . Indeed, if i = 1 , , ρ , then P A y i = P x i = y i , and if i = ρ + 1 , , n , then P A y i = P 0 = 0 . ◻

Consideration of the adjoint of A , together with the reflexivity of 𝒱 , shows that we may also find an invertible Q for which A Q is a projection. In case A itself is invertible, we must have P = Q = A 1 .

EXERCISES

Exercise 1. What is the rank of the differentiation operator on 𝒫 n ? What is its nullity?

Exercise 2. Find the ranks of the following matrices.

  1. [ 1 1 1 1 1 1 1 1 1 ]  
  2. [ 1 1 1 1 1 0 1 0 0 ]  
  3. [ 0 0 1 0 1 0 1 0 0 ]  
  4. [ 0 1 0 1 0 1 0 1 0 ]  

Exercise 3. If A is left multiplication by P on a space of linear transformations (cf. Section: Matrices of transformations , Ex. 5), and if P has rank m , what is the rank of A ?

Exercise 4. The rank of the direct sum of two linear transformations (on finite-dimensional vector spaces) is the sum of their ranks.

Exercise 5. 

  1. If A and B are linear transformations on an n -dimensional vector space, and if A B = 0 , then ρ ( A ) + ρ ( B ) n .
  2. For each linear transformation A on an n -dimensional vector space there exists a linear transformation B such that A B = 0 and such that ρ ( A ) + ρ ( B ) = n .

Exercise 6. If A , B , and C are linear transformations on a finite-dimensional vector space, then ρ ( A B ) + ρ ( B C ) ρ ( B ) + ρ ( A B C ) .  

Exercise 7. Prove that two linear transformations (on the same finite-dimensional vector space) are equivalent if and only if they have the same rank.

Exercise 8. 

  1. Suppose that A and B are linear transformations (on the same finite-dimensional vector space) such that A 2 = A and B 2 = B . Is it true that A and B are similar if and only if ρ ( A ) = ρ ( B ) ?
  2. Suppose that A and B are linear transformations (on the same finite-dimensional vector space) such that A 0 , B 0 , and A 2 = B 2 = 0 . Is it true that A and B are similar if and only if ρ ( A ) = ρ ( B ) ?

Exercise 9. 

  1. If A is a linear transformation of rank one, then there exists a unique scalar α such that A 2 = α A .
  2. If α 1 , then 1 A is invertible.