Exponential Functions

An exponential function $f(x) = b^x$ places the variable in the exponent rather than the base. This simple shift produces functions with remarkable properties: they grow (or decay) at a rate proportional to their current value, they are defined for all real $x$, and they are always positive. Understanding their graphs and transformations is the foundation for logarithms, compound interest, population models, and calculus.

Quick Reference

Property Formula / Value
General form $f(x) = b^x$, where $b > 0$, $b \neq 1$
Domain $(-\infty, \infty)$
Range $(0, \infty)$
$y$-intercept $(0, 1)$ for every base $b$
Asymptote $x$-axis ($y = 0$)
$b > 1$ Increasing (exponential growth)
$0 < b < 1$ Decreasing (exponential decay)
Reflection in $y$-axis $(1/b)^x = b^{-x}$
Natural base $e \approx 2.71828\ldots$

Definition and Basic Properties

A function of the form

$f(x) = b^x$

where $b > 0$ is a fixed constant and $x$ is the variable is called an exponential function with base $b$. The variable appears in the exponent, which is what makes it "exponential."

The requirement $b > 0$ is essential: when $b < 0$, the expression $b^x$ is only defined for specific rational values of $x$ (those with odd-integer denominators), so the function would not have a continuous domain. Requiring $b > 0$ ensures $f(x) = b^x$ is defined for all real $x$. The case $b = 1$ gives the constant function $1^x = 1$, which is uninteresting.

Three key properties hold for every exponential function $f(x) = b^x$ (with $b > 0$, $b \neq 1$):

  • The expression $b^x$ is defined for all real $x$, so the domain of $f$ is $(-\infty, \infty)$.
  • Since $b^x > 0$ for any $x$, the graph of $f$ always lies above the $x$-axis; the range is $(0, \infty)$.
  • Since $b^0 = 1$, the graph passes through $(0, 1)$: every exponential function shares the same $y$-intercept.

If $f(x) = b^x$ with $b > 0$, $b \neq 1$:

$\operatorname{Dom}(f) = \mathbb{R} = (-\infty,\infty) \qquad \text{and} \qquad \operatorname{Rng}(f) = (0,\infty).$

Graphs of Exponential Functions

The shape of the graph depends critically on whether $b > 1$ or $0 < b < 1$.

When b  >  1: Exponential Growth

When $b > 1$, the function $y = b^x$ increases as $x$ increases. For large positive $x$, the value of $y$ becomes very large. For large negative $x$, the value of $y$ approaches zero from above: the graph hugs the negative $x$-axis but never touches it. The $x$-axis is a horizontal asymptote.

Graphs of exponential functions y = bˣ for bases b  loading= 1 (2ˣ, 3ˣ, 1.5ˣ), showing exponential growth.">
Graphs of exponential functions $y = b^x$ when $b > 1$. All pass through $(0,1)$ and grow without bound as $x \to \infty$.

When $0 < b < 1$: Exponential Decay

When $0 < b < 1$, the function $y = b^x$ decreases as $x$ increases. As $x \to +\infty$, the value approaches zero; as $x \to -\infty$, the value grows without bound. The range is still $(0, \infty)$.

Graphs of exponential functions y = bˣ for bases 0 < b < 1 (0.5ˣ, 0.2ˣ), showing exponential decay.
Graphs of exponential functions $y = b^x$ when $0 < b < 1$. All pass through $(0,1)$ and decay toward zero as $x \to \infty$.

Symmetry Between Reciprocal Bases

The graphs of $y = b^x$ and $y = (1/b)^x$ are reflections of each other in the $y$-axis. To see why, note that

$(1/b)^x = b^{-x}.$

The function $y = b^{-x}$ takes the same values for positive $x$ as $y = b^x$ takes for negative $x$ of the same magnitude, and vice versa. This is exactly what reflection in the $y$-axis does.

Graphs showing the symmetry between exponential functions with reciprocal bases (e.g., 2ˣ and (½)ˣ) across the y-axis.
The graphs of $y = b^x$ and $y = (1/b)^x = b^{-x}$ are symmetric with respect to the $y$-axis.

Because $1/b > 1$ whenever $0 < b < 1$, and $0 < 1/b < 1$ whenever $b > 1$, every decaying exponential corresponds to a growing one obtained by replacing $b$ with $1/b$.

Exponential Growth Vs. Polynomial Growth

Comparison graph of exponential growth (2ˣ) versus polynomial growth (x²), showing the exponential eventually overtaking the polynomial.
The graphs of $y = 2^x$ and $y = x^2$ intersect at three points, but for $x > 4$, the exponential $2^x$ dominates and the gap widens steeply.

When $b > 1$, the exponential function $y = b^x$ eventually outgrows any polynomial $y = x^n$, no matter how large $n$ is. For example, with $b = 1.1$ and $n = 10$: at $x = 1000$, the polynomial $x^{10}$ equals $10^{30}$, while $1.1^{1000} \approx 2.47 \times 10^{41}$, roughly $2.5 \times 10^{11}$ times larger.

Graphing Transformations of Exponential Functions

Sketch the graph of each function and determine its domain and range.

  1. $f(x) = 1 - 3^x$
  2. $g(x) = 3^{-x} - 2$
Solution (a) Since the base 3 is positive, there is no restriction on $x$. The domain of $f$ is $(-\infty, \infty)$. To graph $f(x) = 1 - 3^x$, we use transformations starting from $y = 3^x$: Step 1. Begin with $y = 3^x$:
Graph of the exponential function y = 3ˣ.
Graph of $y = 3^x$
Step 2. Reflect in the $x$-axis to obtain $y = -3^x$:
Graph showing the reflection of y = 3ˣ across the x-axis to form y = -3ˣ.
Graphs of $y = 3^x$ and $y = -3^x$
Step 3. Shift upward 1 unit to obtain $y = 1 - 3^x$:
Graph showing the vertical shift of y = -3ˣ up 1 unit to form y = 1 - 3ˣ.
Graphs of $y = -3^x$ and $y = 1 - 3^x$
The range of $f$ is $(-\infty, 1)$. We verify algebraically: since $0 < 3^x < \infty$, we have $-\infty < -3^x < 0 \implies -\infty < 1 - 3^x < 1.$ (b) Again the domain is $\mathbb{R}$. To graph $g(x) = 3^{-x} - 2$: Step 1. Begin with $y = 3^x$ (same starting graph). Step 2. Reflect in the $y$-axis to obtain $y = 3^{-x}$:
Graph showing the reflection of y = 3ˣ across the y-axis to form y = 3⁻ˣ.
Graphs of $y = 3^x$ and $y = 3^{-x}$
Step 3. Shift downward 2 units to obtain $y = 3^{-x} - 2$:
Graph showing the vertical shift of y = 3⁻ˣ down 2 units to form y = 3⁻ˣ - 2.
Graphs of $y = 3^{-x}$ and $y = 3^{-x} - 2$
The range of $g$ is $(-2, \infty)$. Verification: since $0 < 3^x < \infty$, a reflection in the $y$-axis does not change the range, so $0 < 3^{-x} < \infty$, and shifting down 2 gives $-2 < 3^{-x} - 2 < \infty.$

The Natural Exponential Function

The natural exponential function is $f(x) = e^x$, where

$e = 2.71828182845904523536\ldots$

is an irrational constant called Euler's number (also known as Napier's constant). The function $e^x$ is also written $\exp(x)$.

The number $e$ is irrational (like $\pi$), and its graph $y = e^x$ sits between $y = 2^x$ and $y = 3^x$ because $2 < e < 3$:

Graph of the natural exponential function y = eˣ plotted between y = 2ˣ and y = 3ˣ.
The natural exponential function $y = e^x$, with $e = 2.71828\ldots$, lies between $y = 2^x$ and $y = 3^x$.

The natural exponential is called "the" exponential function because it is the unique function satisfying $f'(x) = f(x)$: its rate of change equals its current value at every point. Many calculators have a dedicated key for $e^x$, and note that $e = \exp(1)$.

Frequently Asked Questions

Why can't the base of an exponential function be negative? When the base $b$ is negative, $b^x$ is only defined when $x$ is a rational number $p/q$ with $q$ odd. This leaves the function undefined for irrational $x$ and many rationals, so it cannot be graphed as a continuous curve. Calculus requires functions to be defined for all real $x$, which is why exponential functions require $b > 0$.

What is the horizontal asymptote of an exponential function? The horizontal asymptote of $y = b^x$ is the $x$-axis, i.e., $y = 0$. When $b > 1$ the curve approaches $y = 0$ as $x \to -\infty$; when $0 < b < 1$ it approaches $y = 0$ as $x \to +\infty$. Transformations shift this asymptote: for example, $y = b^x + k$ has horizontal asymptote $y = k$.

How do I graph transformations of exponential functions? Use the standard transformation toolkit applied to $y = b^x$:
  • $y = b^{x-h}$: horizontal shift right by $h$
  • $y = b^x + k$: vertical shift up by $k$
  • $y = -b^x$: reflection in the $x$-axis (range becomes $(-\infty, 0)$)
  • $y = b^{-x}$: reflection in the $y$-axis (equivalent to $(1/b)^x$)
  • $y = a \cdot b^x$: vertical stretch by factor $|a|$
Work through transformations step by step, tracking the $y$-intercept and asymptote at each stage.

Does the exponential function eventually beat every polynomial? Yes. For any base $b > 1$ and any polynomial $x^n$ (no matter how large $n$ is), the exponential $b^x$ eventually dominates: as $x \to \infty$, $b^x / x^n \to \infty$. This is often stated as "exponentials grow faster than any polynomial." The crossover point may be very far to the right for small $b$ or large $n$, but the exponential always wins in the long run.

What is the significance of $e$ compared to other bases? The number $e$ is the unique base for which $\frac{d}{dx}[b^x] = b^x$ exactly, with no extra constant factor. For any other base, $\frac{d}{dx}[b^x] = b^x \ln b$, which is only equal to $b^x$ when $\ln b = 1$, i.e., when $b = e$. This self-referential derivative property makes $e^x$ the natural choice for modeling continuous growth, solving differential equations, and simplifying integrals throughout calculus.