Absolute Value of a Complex Number and Complex Conjugates
The absolute value (or modulus) of a complex number is its distance from the origin in the complex plane:
The complex conjugate of is , obtained by reflecting across the real axis.
Quick Reference
| Concept | Formula | Example |
|---|---|---|
| Modulus | \bar{z} = a - bi\overline{3 + 4i} = 3 - 4iz \bar{z} | z |
| Product of moduli | z/w | |
| Modulus of conjugate | z = x + yi|z|$ is the distance from the point $z|z| \geq 0$ for all complex numbers $z|z| = 0$ if and only if $z = 0x = 0y = 0a + 0i|a + 0i| = \sqrt{a^2} = |a|3 + 4i-2 + 0i0 + 5izw$ (with $w \neq 0|zw| = |z||w|z = a + biw = c + di|zw| = |z||w|z = a + bi\bar{z}$ is the reflection of $zz + \bar{z} = 2a = 2\operatorname{Re}(z)z - \bar{z} = 2bi = 2i\operatorname{Im}(z)z\bar{z} = a^2 + b^2 = |z|^2\overline{z + w} = \bar{z} + \bar{w}\overline{zw} = \bar{z}\,\bar{w}\overline{\bar{z}} = z|\bar{z}| = |z|z = 2 - 3i$. Find $\bar{z}z + \bar{z}z - \bar{z}z\bar{z}\bar{z} = 2 + 3iz + \bar{z} = (2 - 3i) + (2 + 3i) = 4z - \bar{z} = (2 - 3i) - (2 + 3i) = -6iz\bar{z} = (2 - 3i)(2 + 3i) = 4 + 9 = 13 = |z|^2z \bar{z} = |z|^2$ is a positive real number (for $z \neq 0$), the reciprocal of $z1 + 2i|a| = \sqrt{a^2}a$, the modulus $|a + 0i| = \sqrt{a^2} = |a|z\bar{z}z = a + biz\bar{z} = (a+bi)(a-bi) = a^2 + b^2$. This is a sum of squares of real numbers, so it is always non-negative. It equals zero only when $a = b = 0z = 0\bar{z}$ is the reflection of $z$ across the real (horizontal) axis. If $z = a + bi$ is plotted at $(a, b)$, then $\bar{z} = a - bi$ is plotted at $(a, -b)z_1z_2$ in the complex plane equals $|z_1 - z_2|$. This generalizes the idea that $|z|$ is the distance from $z|zw| = |z||w|w$ scales distances by the factor $|w|$. This is fundamental to understanding multiplication geometrically (rotation and scaling), which is developed further in polar form and Euler's formula in more advanced courses. |